IPMAT Indore 2026 · Quantitative Ability · Question 35
IPMAT Indore 2026 previous year question on Probability, with the answer and a step-by-step solution.
- A\frac{1}{108}
- B\frac{7}{216}
- C\frac{1}{54}
- D\frac{1}{27}
Answer & solution
Answer: Option C
Step 1 — understand the ceiling. Three rolls give a maximum of 6+6+6=18, so “at least 17” means the sum is 17 or 18.
Step 2 — count the favourable outcomes.
Sum 18: only \left( 6,6,6 \right) — 1 way.
Sum 17: the multiset must be \{6,6,5\}, which can be ordered in \frac{3!}{2!}=3 ways — 3 ways.
\text{Total favourable}=1+3=4
Step 3 — divide by the sample space.
P=\frac{4}{216}=\frac{1}{54}
Answer: Option 3 — \frac{1}{54}
Shortcut. Count downward from the maximum, not upward from 17 — only two sums are possible, and each has an obvious shape. The distractor \frac{7}{216} belongs to “at least 16”.
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