IPMAT Indore 2023 · Quantitative Ability · Question 3
IPMAT Indore 2023 previous year question on Time and Work, with the answer and a step-by-step solution.
Answer & solution
Answer: 24
Step 1 — Amisha’s rates. Her full rate is \frac{1}{20} of the task per day; her halved rate is \frac{1}{40}.
Step 2 — account for the work in three phases.
Phase | Days | Who works | Work done |
|---|---|---|---|
Days 1–4 | 4 | Amisha at full rate | 4\times 1/20=1/5 |
Days 5–8 | 4 | nobody (she is ill) | 0 |
Days 9–20 | 12 | Amisha at half rate + co-worker | 12\times 1/40+12r |
Step 3 — set the total to one whole task. Let the co-worker’s rate be r per day.
\frac{1}{5}+\frac{12}{40}+12r=1
\frac{4}{20}+\frac{6}{20}+12r=1 \Rightarrow \frac{10}{20}+12r=1 \Rightarrow 12r=\frac{1}{2}
Step 4 — invert.
r=\frac{1}{24}\Rightarrow \text{the co-worker alone needs}24\text{days}
Answer: 24
Shortcut. Work in units, not fractions. Let the task be 40 units (the lcm of 20 and 40). Amisha does 2 units/day at full rate, 1 unit/day at half rate.
Days 1–4: 4\times 2=8 units
Days 9–20: 12\times 1=12 units
That is 20 of the 40 units, so the co-worker supplies the other 20 units in 12 days. Alone, he needs
\frac{40}{20/12}=24\text{days}
The sick days are a red herring — they contribute nothing and only exist to make you lose track of the day count. Tabulating the phases prevents that.
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