CAT 2025 Slot 2 · Quant · Question 17
CAT 2025 Slot 2 previous year question on Averages, Mixture and Alligation, with the answer and a step-by-step solution.
- A4
- B6
- C2.5
- D5
Answer & solution
Answer: Option D
A mixture that is a fraction f coffee costs f\times \left( \text{coffee rate}\right)+\left( 1-f \right)\times \left( \text{cocoa rate}\right), which is a straight line in f.
Coffee content rises from 16% to 36%, a gain of 20 percentage points, while the price rises from 240 to 320, a gain of 80.
Scaling up, the full 100 points from pure cocoa to pure coffee cost 80\times 5=400.
Pure cocoa therefore costs 240-0.16\times 400=176 per kg, and pure coffee 176+400=576 per kg.
For the new mixture, 576f+176\left( 1-f \right)=376.
That simplifies to 176+400f=376, so 400f=200 and f=0.5.
Half of 10 kg is 5 kg of coffee.
Shortcut. Work in price differences only. From the 36% mixture at 320, the new mixture is 56 dearer. Since 80 rupees buys 20 percentage points, 56 rupees buys \frac{56}{80}\times 20=14 points. So the coffee content is 36+14=50\%, giving 5 kg — the pure rates never need to be found.
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