CAT 2023 Slot 2 · Quant · Question 8

CAT 2023 Slot 2 previous year question on Averages, Mixture and Alligation, with the answer and a step-by-step solution.

Averages, Mixture and AlligationArithmeticMultiple choiceMedium
In a company, 20% of the employees work in the manufacturing department. If the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company, then the ratio of the average salary obtained by the manufacturing employees to the average salary obtained by the non-manufacturing employees is
  1. A
    4 : 5
  2. B
    5 : 6
  3. C
    5 : 4
  4. D
    6 : 5
Pick an option, then check.
Answer & solution

Answer: Option A

Take the company as 100 employees with a total salary bill of 600 units, chosen so the fractions stay whole.

Manufacturing employs 20% of them, that is 20 people, leaving 80 in other departments.

Manufacturing earns one-sixth of the total, that is \frac{600}{6}=100 units.

The non-manufacturing employees therefore earn 600-100=500 units.

The manufacturing average is \frac{100}{20}=5 units per person.

The non-manufacturing average is \frac{500}{80}=6.25 units per person.

The ratio is 5:6.25, and multiplying both sides by 4 gives 20:25.

Dividing by 5, the ratio is 4:5 — the first option.

Shortcut. Average is total divided by headcount, so the ratio of averages is the ratio of salary shares divided by the ratio of headcount shares. That is \frac{1/6}{5/6}\div \frac{20}{80}=\frac{1}{5}\div \frac{1}{4}=\frac{4}{5} in one line.

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