CAT 2022 Slot 2 · DILR · Question 8
CAT 2022 Slot 2 previous year question on Caselet DI, with the answer and a step-by-step solution.
Set 2: Widget Deliveries from a Warehouse — this question belongs to a set. Read the full set with all 5 questions →
Every day a widget supplier supplies widgets from the warehouse (W) to four locations - Ahmednagar (A), Bikrampore (B), Chitrachak (C), and Deccan Park (D). The daily demand for widgets in each location is uncertain and independent of each other. Demands and corresponding probability values (in parenthesis) are given against each location (A, B, C, and D) in the figure below. For example, there is a 40% chance that the demand in Ahmednagar will be 50 units and a 60% chance that the demand will be 70 units. The lines in the figure connecting the locations and warehouse represent two-way roads connecting those places with the distances (in km) shown beside the line. The distances in both the directions along a road are equal. For example, the road from Ahmednagar to Bikrampore and the road from Bikrampore to Ahmednagar are both 6 km long.
Every day the supplier gets the information about the demand values of the four locations and creates the travel route that starts from the warehouse and ends at a location after visiting all the locations exactly once. While making the route plan, the supplier goes to the locations in decreasing order of demand. If there is a tie for the choice of the next location, the supplier will go to the location closest to the current location. Also, while creating the route, the supplier can either follow the direct path (if available) from one location to another or can take the path via the warehouse. If both paths are available (direct and via warehouse), the supplier will choose the path with minimum distance.
- A33.33%
- B10.80%
- C17.64%
- D7.56%
Answer & solution
Answer: Option D
Solving the set
Step 1 – Shortest allowed distances between locations (direct road, or via the warehouse; the smaller one is used).
From / To | A | B | C | D |
W | 5 | 10 | 12 | 2 |
A | — | 6 (direct) | 17 (via W) | 7 (via W; direct is 8) |
B | 6 | — | 4 (direct) | 12 (via W) |
C | 17 | 4 | — | 6 (direct) |
D | 7 | 12 | 6 | — |
Step 2 – Routes. Visit in decreasing order of demand; for a tie, go to the nearer location from where the supplier is. The 16 demand combinations, their probabilities (product of the four probabilities), routes and distances are:
A | B | C | D | Probability | Route | Distance (km) | Total units |
50 | 40 | 70 | 30 | 1.44% | W-C-A-B-D | 47 | 190 |
50 | 40 | 70 | 50 | 2.16% | W-C-D-A-B | 31 | 210 |
50 | 40 | 100 | 30 | 3.36% | W-C-A-B-D | 47 | 220 |
50 | 40 | 100 | 50 | 5.04% | W-C-D-A-B | 31 | 240 |
50 | 60 | 70 | 30 | 3.36% | W-C-B-A-D | 29 | 210 |
50 | 60 | 70 | 50 | 5.04% | W-C-B-A-D | 29 | 230 |
50 | 60 | 100 | 30 | 7.84% | W-C-B-A-D | 29 | 240 |
50 | 60 | 100 | 50 | 11.76% | W-C-B-A-D | 29 | 260 |
70 | 40 | 70 | 30 | 2.16% | W-A-C-B-D | 38 | 210 |
70 | 40 | 70 | 50 | 3.24% | W-A-C-D-B | 40 | 230 |
70 | 40 | 100 | 30 | 5.04% | W-C-A-B-D | 47 | 240 |
70 | 40 | 100 | 50 | 7.56% | W-C-A-D-B | 48 | 260 |
70 | 60 | 70 | 30 | 5.04% | W-A-C-B-D | 38 | 230 |
70 | 60 | 70 | 50 | 7.56% | W-A-C-B-D | 38 | 250 |
70 | 60 | 100 | 30 | 11.76% | W-C-A-B-D | 47 | 260 |
70 | 60 | 100 | 50 | 17.64% | W-C-A-B-D | 47 | 280 |
This question
Rows of the table with 260 units: (50, 60, 100, 50) ends at D; (70, 40, 100, 50) ends at B; (70, 60, 100, 30) ends at D. Only the middle one ends at B.
Probability = 0.6 (A = 70) × 0.3 (B = 40) × 0.7 (C = 100) × 0.6 (D = 50) = 0.0756 = 7.56%.
Hence, the answer is option 4.
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