CAT 2022 Slot 2 · DILR · Question 7

CAT 2022 Slot 2 previous year question on Caselet DI, with the answer and a step-by-step solution.

Caselet DIData InterpretationType in the answer (TITA)Medium

Set 2: Widget Deliveries from a Warehouse — this question belongs to a set. Read the full set with all 5 questions →

Every day a widget supplier supplies widgets from the warehouse (W) to four locations - Ahmednagar (A), Bikrampore (B), Chitrachak (C), and Deccan Park (D). The daily demand for widgets in each location is uncertain and independent of each other. Demands and corresponding probability values (in parenthesis) are given against each location (A, B, C, and D) in the figure below. For example, there is a 40% chance that the demand in Ahmednagar will be 50 units and a 60% chance that the demand will be 70 units. The lines in the figure connecting the locations and warehouse represent two-way roads connecting those places with the distances (in km) shown beside the line. The distances in both the directions along a road are equal. For example, the road from Ahmednagar to Bikrampore and the road from Bikrampore to Ahmednagar are both 6 km long.

Every day the supplier gets the information about the demand values of the four locations and creates the travel route that starts from the warehouse and ends at a location after visiting all the locations exactly once. While making the route plan, the supplier goes to the locations in decreasing order of demand. If there is a tie for the choice of the next location, the supplier will go to the location closest to the current location. Also, while creating the route, the supplier can either follow the direct path (if available) from one location to another or can take the path via the warehouse. If both paths are available (direct and via warehouse), the supplier will choose the path with minimum distance.

If the total number of widgets delivered in a day is 250 units, then what is the total distance covered in the route (in km)?
Answer & solution

Answer: 38

Solving the set

Step 1 – Shortest allowed distances between locations (direct road, or via the warehouse; the smaller one is used).

From / To

A

B

C

D

W

5

10

12

2

A

—

6 (direct)

17 (via W)

7 (via W; direct is 8)

B

6

—

4 (direct)

12 (via W)

C

17

4

—

6 (direct)

D

7

12

6

—

Step 2 – Routes. Visit in decreasing order of demand; for a tie, go to the nearer location from where the supplier is. The 16 demand combinations, their probabilities (product of the four probabilities), routes and distances are:

A

B

C

D

Probability

Route

Distance (km)

Total units

50

40

70

30

1.44%

W-C-A-B-D

47

190

50

40

70

50

2.16%

W-C-D-A-B

31

210

50

40

100

30

3.36%

W-C-A-B-D

47

220

50

40

100

50

5.04%

W-C-D-A-B

31

240

50

60

70

30

3.36%

W-C-B-A-D

29

210

50

60

70

50

5.04%

W-C-B-A-D

29

230

50

60

100

30

7.84%

W-C-B-A-D

29

240

50

60

100

50

11.76%

W-C-B-A-D

29

260

70

40

70

30

2.16%

W-A-C-B-D

38

210

70

40

70

50

3.24%

W-A-C-D-B

40

230

70

40

100

30

5.04%

W-C-A-B-D

47

240

70

40

100

50

7.56%

W-C-A-D-B

48

260

70

60

70

30

5.04%

W-A-C-B-D

38

230

70

60

70

50

7.56%

W-A-C-B-D

38

250

70

60

100

30

11.76%

W-C-A-B-D

47

260

70

60

100

50

17.64%

W-C-A-B-D

47

280

This question

Total 250 occurs only for A = 70, B = 60, C = 70, D = 50 (70 + 60 + 70 + 50). From W, A and C tie at 70; A is closer (5 km vs 12 km). Then C (17 km via W), then B (60, 4 km), then D (50, 12 km via W). Route W-A-C-B-D = 5 + 17 + 4 + 12 = 38 km.

Hence, the answer is 38.

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