CAT 2021 Slot 3 · Quant · Question 8
CAT 2021 Slot 3 previous year question on Linear Equations, with the answer and a step-by-step solution.
- A20800
- B20200
- C20500
- D20000
Answer & solution
Answer: Option C
Let the monthly expense for n boarders be F+kn, where F is fixed. Revenue is 1600n, so total profit is 1600n-F-kn.
At n=50 the profit is 200 per boarder, so 10000 in total: 80000-F-50k=10000, giving F+50k=70000.
At n=75 the profit is 250 per boarder, so 18750 in total: 120000-F-75k=18750, giving F+75k=101250.
Subtracting, 25k=31250, so k=1250 and then F=70000-62500=7500.
At n=80: profit =1600\times 80-7500-1250\times 80=128000-7500-100000=20500, that is ₹20500.
Note the question asks for the total profit here, not the profit per boarder.
More Linear Equations questions
- Q6A basket of 2 apples, 4 oranges and 6 mangoes costs the same as a basket of 1 apple, 4 oranges and 8 mangoes, or a…CAT 2021 Slot 1 · Quant · Linear Equations
- Q3Consider the pair of equations: x²-xy-x=22 and y²-xy+y=34 . If x>y , then x-y equalsCAT 2021 Slot 2 · Quant · Linear Equations
- Q1If a-6b+6c=4 and 6a+3b-3c=50 , where a , b and c are real numbers, the value of 2a+3b-3c isCAT 2025 Slot 1 · Quant · Linear Equations
- Q20Stocks A, B and C are priced at ₹120, ₹90 and ₹150 per share, respectively. A trader holds a portfolio consisting of…CAT 2025 Slot 1 · Quant · Linear Equations
- Q15A shop owner bought a total of 64 shirts from a wholesale market that came in two sizes, small and large. The price of…CAT 2021 Slot 3 · Quant · Linear Equations
- Q17A tea shop offers tea in cups of three different sizes. The product of the prices, in ₹, of three different sizes is…CAT 2021 Slot 3 · Quant · Linear Equations
Take this paper as a timed test
Real exam timing, instant score, rank and topic-wise analysis.