IPMAT Indore 2025 · Quantitative Ability · Question 6
IPMAT Indore 2025 previous year question on Deductive Reasoning, with the answer and a step-by-step solution.
Set 1: Five expedition teams – biologists, geologists and explorers — this question belongs to a set. Read the full set with all 3 questions →
Five teams — A, B, C, D, and E — each consisting of 15 members, are going on expeditions to five different locations. Each team includes members from three different skill sets: biologists, geologists, and explorers. However, the number of members from each skill set varies by team, and each member has only one speciality. The total number of biologists, geologists, and explorers is equal.
The following additional information is available:
Every team has at least 2 members from each skill set.
Teams C and D have 6 biologists each, and Team A has 6 geologists.
Every team except A has more biologists than explorers.
The number of explorers in each team is distinct and decreases in the order A, B, C, D, and E.
Answer & solution
Answer: 2
Five teams of 15 members each, every member a biologist, a geologist or an explorer.
Team | Biologists | Geologists | Explorers | Row total |
|---|---|---|---|---|
A | ? | 6 | ? | 15 |
B | ? | ? | ? | 15 |
C | 6 | ? | ? | 15 |
D | 6 | ? | ? | 15 |
E | ? | ? | ? | 15 |
Total | ? | ? | ? | 75 |
Four rules stay on the board throughout:
Every cell is at least 2
The three skills are shared equally across all 75 members
Explorer counts are all different and strictly decrease from A to E
Teams B, C, D and E each have more biologists than explorers
Step 1 — each column totals 25
75 members shared equally among 3 skills gives 75 ÷ 3 = 25 per column.
Team | Biologists | Geologists | Explorers | Row total |
|---|---|---|---|---|
A | ? | 6 | ? | 15 |
B | ? | ? | ? | 15 |
C | 6 | ? | ? | 15 |
D | 6 | ? | ? | 15 |
E | ? | ? | ? | 15 |
Total | 25 | 25 | 25 | 75 |
Step 2 — Team A caps the explorers at 7
Row A totals 15 and 6 of them are geologists, so biologists + explorers = 9. Since biologists must be at least 2, Team A can hold at most 7 explorers.
Team | Biologists | Geologists | Explorers | Row total |
|---|---|---|---|---|
A | ≥ 2 | 6 | ≤ 7 | 15 |
B | ? | ? | ? | 15 |
C | 6 | ? | ? | 15 |
D | 6 | ? | ? | 15 |
E | ? | ? | ? | 15 |
Total | 25 | 25 | 25 | 75 |
Team A holds the largest explorer count, so this cap is really a cap on the whole explorer column.
Step 3 — the explorer column is forced
We need five different values, decreasing, smallest at least 2, largest at most 7, adding to 25. Only {2, 3, 4, 5, 6, 7} are available and they add to 27, so exactly one of them is dropped — and dropping the 2 is the only way to land on 25.
Candidate set | Sum | Verdict |
|---|---|---|
6, 5, 4, 3, 2 | 20 | too small |
7, 5, 4, 3, 2 | 21 | too small |
7, 6, 4, 3, 2 | 22 | too small |
7, 6, 5, 3, 2 | 23 | too small |
7, 6, 5, 4, 2 | 24 | too small |
7, 6, 5, 4, 3 | 25 | only fit |
Team A's biologists come free here: 9 − 7 = 2.
Team | Biologists | Geologists | Explorers | Row total |
|---|---|---|---|---|
A | 2 | 6 | 7 | 15 |
B | ? | ? | 6 | 15 |
C | 6 | ? | 5 | 15 |
D | 6 | ? | 4 | 15 |
E | ? | ? | 3 | 15 |
Total | 25 | 25 | 25 | 75 |
Step 4 — Team B is squeezed from both sides
Two separate rules push Team B's biologists to the same number from opposite directions.
Pressure from | Reasoning | Result |
|---|---|---|
Biologists > explorers | explorers = 6 | at least 7 |
Geologists ≥ 2 | biologists + geologists = 15 − 6 = 9 | at most 7 |
Both arrows point at 7, so Team B has 7 biologists and 2 geologists.
Team | Biologists | Geologists | Explorers | Row total |
|---|---|---|---|---|
A | 2 | 6 | 7 | 15 |
B | 7 | 2 | 6 | 15 |
C | 6 | ? | 5 | 15 |
D | 6 | ? | 4 | 15 |
E | ? | ? | 3 | 15 |
Total | 25 | 25 | 25 | 75 |
Step 5 — Team E's biologists by subtraction
The biologist column must reach 25, and four of its five entries are now known: 2 + 7 + 6 + 6 = 21, leaving 4 for Team E.
Check the rule: 4 biologists beats 3 explorers, so Team E still satisfies the biologists > explorers condition.
Team | Biologists | Geologists | Explorers | Row total |
|---|---|---|---|---|
A | 2 | 6 | 7 | 15 |
B | 7 | 2 | 6 | 15 |
C | 6 | ? | 5 | 15 |
D | 6 | ? | 4 | 15 |
E | 4 | ? | 3 | 15 |
Total | 25 | 25 | 25 | 75 |
Step 6 — the last geologists
Each remaining geologist cell is whatever the row needs to reach 15.
Team | 15 − biologists − explorers | Geologists |
|---|---|---|
C | 15 − 6 − 5 | 4 |
D | 15 − 6 − 4 | 5 |
E | 15 − 4 − 3 | 8 |
Final table and answer
Team E has 4 biologists.
Team | Biologists | Geologists | Explorers | Row total |
|---|---|---|---|---|
A | 2 | 6 | 7 | 15 |
B | 7 | 2 | 6 | 15 |
C | 6 | 4 | 5 | 15 |
D | 6 | 5 | 4 | 15 |
E | 4 | 8 | 3 | 15 |
Total | 25 | 25 | 25 | 75 |
Verification sweep:
Every cell is at least 2
All three columns total 25
Explorers run 7, 6, 5, 4, 3 — distinct and strictly decreasing
B, C, D and E each have more biologists than explorers: 7 > 6, 6 > 5, 6 > 4, 4 > 3
IMPORTANT NOTE — 3 moves
In the exam, only three moves actually matter. Everything else is arithmetic.
Move | What it uses | What it gives |
|---|---|---|
1 | Columns are 25 each. In Team A, biologists + explorers = 9, and biologists ≥ 2, so explorers ≤ 7. Five distinct values, each ≥ 2, largest ≤ 7, summing to 25 | Explorers = 7, 6, 5, 4, 3 and Team A has 2 biologists |
2 | Team B has 6 explorers, so biologists ≥ 7; but geologists ≥ 2 forces biologists ≤ 7 | Team B has 7 biologists |
3 | Biologist column: 25 − (2 + 7 + 6 + 6) | Team E has 4 biologists |
Move 1 is the whole puzzle. Teach students to hunt for the row with a given value (Team A's 6 geologists) and turn it into a cap on the constrained column.
Answer: 2
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