IPMAT Indore 2025 · Quantitative Ability · Question 28
IPMAT Indore 2025 previous year question on Simple Interest and Compound Interest, with the answer and a step-by-step solution.
- A10308
- B11748
- C22348
- D19708
Answer & solution
Answer: Option B
Step 1 — split the principal. A gets ₹30,000, so B and C share the rest:
B+C=100000-30000=70000
Step 2 — use the first-year interest.
\underset{3000}{\underset{⏟}{0.10\times 30000}}+0.08B+0.12C=10600 \Rightarrow 0.08B+0.12C=7600
Substituting B=70000-C:
0.08\left( 70000-C \right)+0.12C=7600
5600+0.04C=7600 \Rightarrow C=50000, B=20000
Step 3 — grow each principal by one year (this is what “compounded annually” means — year 2 earns interest on year 1’s closing balance):
Scheme | Rate | Start | After year 1 |
|---|---|---|---|
A | 10% | 30,000 | 33,000 |
B | 8% | 20,000 | 21,600 |
C | 12% | 50,000 | 56,000 |
Step 4 — second-year interest.
0.10\left( 33000 \right)+0.08\left( 21600 \right)+0.12\left( 56000 \right)
=3300+1728+6720=11748
Answer: Option 2 — ₹11,748
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