IPMAT Indore 2022 · Quantitative Ability · Question 33
IPMAT Indore 2022 previous year question on HCF and LCM, with the answer and a step-by-step solution.
- Athe product of the LCM and HCF of the two numbers
- Bthe HCF of the two numbers
- Cthe LCM of the two numbers
- Dthe square of the product of the two numbers
Answer & solution
Answer: Option A
Step 1 — translate the words into algebra. Let the two natural numbers be a and b. The description says:
\frac{{\left( a+b \right)}^{2}-{\left( a-b \right)}^{2}}{4}
Step 2 — simplify. Expanding,
{\left( a+b \right)}^{2}-{\left( a-b \right)}^{2}=\left({a}^{2}+2ab+{b}^{2}\right)-\left({a}^{2}-2ab+{b}^{2}\right)=4ab
so the whole expression equals
\frac{4ab}{4}=ab
Step 3 — express ab in the language of the options. The fundamental identity relating two numbers to their HCF and LCM:
\text{HCF}\left( a,b \right)\times \text{LCM}\left( a,b \right)=ab
So the result is the product of the LCM and HCF.
Check with a=6, b=4: \frac{100-4}{4}=24, and \text{HCF}=2, \text{LCM}=12, product =24 ✔
Answer: Option 1 — the product of the LCM and HCF of the two numbers
Shortcut. The identity {\left( a+b \right)}^{2}-{\left( a-b \right)}^{2}=4ab is the whole question — divide by 4 and you have ab.
Then recall \text{HCF}\times \text{LCM}=ab, which holds for any two positive integers.
Test the options with one example if you want certainty fast: a=6, b=4 gives 24. The HCF alone is 2, the LCM alone is 12, and {\left( ab \right)}^{2}=576 — so only option (a) matches. One numerical example separates all four options here, which is usually the quickest route when the options are verbal descriptions.
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