IIM B UG (B.Sc-Hons.)- Sample Paper 2026 · Quant & DI · Question 2
IIM B UG (B.Sc-Hons.)- Sample Paper 2026 question on Conic Sections, with the answer and a step-by-step solution.
An ellipse has foci at (−3, 0) and (3, 0), and passes through \left( 3, \frac{16}{5}\right). What is the length of its latus rectum?
- A\frac{18}{5}
- B\frac{32}{5}
- C\frac{25}{4}
- D\frac{16}{5}
Pick an option, then check.
Answer & solution
Answer: Option B
The foci lie on the x-axis at (±3, 0), so c = 3 and the ellipse is x²/a² + y²/b² = 1 with a² = b² + 9.
The given point has x = 3, which is exactly x = c, so its y-coordinate is the semi-latus rectum b²/a.
Therefore b²/a = 16/5, that is b² = 16a/5.
Substituting into a² = b² + 9 gives a² = 16a/5 + 9, or 5a² − 16a − 45 = 0.
Solving: a = (16 + √1156)/10 = (16 + 34)/10 = 5.
Then b² = 16 × 5 ÷ 5 = 16.
Length of the latus rectum = 2b²/a = 32/5.
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