CAT 2025 Slot 3 · Quant · Question 19
CAT 2025 Slot 3 previous year question on Time and Work, with the answer and a step-by-step solution.
- A73
- B76
- C78
- D71
Answer & solution
Answer: Option A
Pipe A fills the tank in 15 hours, so its rate is \frac{1}{15} of the tank per hour.
In the ratio, A corresponds to 4 parts, so one part is \frac{1}{15}\div 4=\frac{1}{60} of the tank per hour.
The three pipes together are 4+9+36=49 parts.
Their combined rate is \frac{49}{60} of the tank per hour.
The time to fill the tank is \frac{60}{49} hours.
In minutes that is \frac{60}{49}\times 60=\frac{3600}{49}=73.47.
The nearest option is 73.
Shortcut. Anchor the ratio to the known pipe: 4 parts take 15 hours, so 1 part would take 60 hours and 49 parts take \frac{60}{49} hours. Reading the ratio as shares of a 60-hour pipe avoids fractions entirely.
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