CAT 2025 Slot 3 · DILR · Question 22
CAT 2025 Slot 3 previous year question on Reasoning Based DI, with the answer and a step-by-step solution.
Set 5: Calls Between Six Friends — this question belongs to a set. Read the full set with all 4 questions →
Anu, Bijay, Chetan, Deepak, Eshan, and Faruq are six friends. Each of them uses a mobile number from exactly one of the two mobile operators - Xitel and Yocel. During the last month, the six friends made several calls to each other. Each call was made by one of these six friends to another. The table below summarizes the number of minutes of calls that each of the six made to (outgoing minutes) and received from (incoming minutes) these friends, grouped by the operators. Some of the entries are missing.
Friend | Operator | Outgoing minutes to | Incoming minutes from | ||
Operator Xitel | Operator Yocel | Operator Xitel | Operator Yocel | ||
Anu | Xitel | 100 | 50 | 225 | |
Bijay | Xitel | 200 | 125 | ||
Chetan | Yocel | 50 | 175 | 250 | 150 |
Deepak | Yocel | 100 | 150 | 275 | 100 |
Eshan | Yocel | 100 | 100 | 375 | |
Faruq | Yocel | 0 | 100 | 150 | |
It is known that the duration of calls from Faruq to Eshan was 200 minutes. Also, there were no calls from:
i. Bijay to Eshan,
ii. Chetan to Anu and Chetan to Deepak,
iii. Deepak to Bijay and Deepak to Faruq,
iv. Eshan to Chetan and Eshan to Deepak.
What was the duration of calls (in minutes) from Deepak to Chetan?
- A
100
- B
125
- C
50
- D
0
Answer & solution
Answer: Option A
From the chain of deductions: Eshan → Faruq = 100, so Chetan → Faruq = 50 (Faruq's incoming from Yocel is 150), so Chetan → Eshan = 175 − 50 = 125.
Eshan receives 375 from Yocel users: 125 from Chetan + 200 from Faruq + Deepak → Eshan, so Deepak → Eshan = 50.
Deepak's outgoing to Yocel is 150, and Deepak → Faruq is zero, so Deepak → Chetan = 150 − 50 = 100.
Shortcut: Eshan's incoming from Yocel pins Deepak → Eshan; subtract it from Deepak's Yocel total.
Hence, the answer is option 1.
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