CAT 2024 Slot 3 · Quant · Question 14
CAT 2024 Slot 3 previous year question on Permutation and Combination, with the answer and a step-by-step solution.
Answer & solution
Answer: 378
Count separately by the number of digits, since the constraints differ.
Single-digit numbers run from 1 to 9, and a single digit cannot repeat, so all 9 qualify.
For two-digit numbers, the first digit has 9 choices (1 to 9, as it cannot be 0).
The second digit may be anything except the first, so it has 9 choices from the ten digits.
That gives 9\times 9=81 two-digit numbers.
For three-digit numbers up to 500, the hundreds digit can only be 1, 2, 3 or 4 — that is 4 choices.
The tens digit is any of the remaining 9 digits, and the units digit any of the remaining 8.
That gives 4\times 9\times 8=288 such numbers.
The number 500 itself has two repeated zeros, so it does not qualify and nothing is added for it.
The total is 9+81+288=378.
Shortcut. Counting the hundreds digit first is what keeps the 500 boundary painless — restricting it to \{1,2,3,4\} covers everything from 100 to 499 in one stroke, and 500 is then dismissed by inspection.
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