CAT 2024 Slot 2 · DILR · Question 10
CAT 2024 Slot 2 previous year question on Reasoning Based DI, with the answer and a step-by-step solution.
Set 3: Daily Product Ratings of an E-commerce Firm — this question belongs to a set. Read the full set with all 4 questions →
An online e-commerce firm receives daily integer product ratings from 1 through 5 given by buyers. The daily average is the average of the ratings given on that day. The cumulative average is the average of all ratings given on or before that day.
The rating system began on Day 1, and the cumulative averages were 3 and 3.1 at the end of Day 1 and Day 2, respectively. The distribution of ratings on Day 2 is given in the figure below.
Distribution of Ratings on Day 2
The following information is known about ratings on Day 3.
1. 100 buyers gave product ratings on Day 3.
2. The modes of the product ratings were 4 and 5.
3. The numbers of buyers giving each product rating are non-zero multiples of 10.
4. The same number of buyers gave product ratings of 1 and 2, and that number is half the number of buyers who gave a rating of 3.
How many buyers gave ratings on Day 1?
Answer & solution
Answer: 150
Solving the set
Step 1 – Day 2 data from the chart.
|
Rating |
Buyers on Day 2 |
Rating × Buyers |
|
1 |
5 |
5 |
|
2 |
10 |
20 |
|
3 |
5 |
15 |
|
4 |
20 |
80 |
|
5 |
10 |
50 |
|
Total |
50 |
170 |
Step 2 – Day 1. Let n buyers rate on Day 1. Their average is 3, so their total is 3n. The cumulative average after Day 2 is 3.1: (3n + 170)/(n + 50) = 3.1 ⇒ 3n + 170 = 3.1n + 155 ⇒ 0.1n = 15 ⇒ n = 150. Day 1 total = 450.
Step 3 – Day 3. Let ratings 1 and 2 each have x buyers; rating 3 then has 2x (fact 4). Ratings 4 and 5 are both modes, so they have the same number y, and y must be more than 2x. Total: x + x + 2x + y + y = 100 ⇒ 4x + 2y = 100. All counts are non-zero multiples of 10.
|
Buyers giving 1 (= giving 2) |
Buyers giving 3 |
Buyers giving 4 (= giving 5) |
Are 4 and 5 the modes? |
|
10 |
20 |
(100 − 40)/2 = 30 |
Yes (30 > 20 > 10) |
|
20 |
40 |
(100 − 80)/2 = 10 |
No (3 has 40 buyers) |
Only x = 10, y = 30 works.
|
Rating |
Buyers on Day 3 |
Rating × Buyers |
Cumulative buyers |
|
1 |
10 |
10 |
1–10 |
|
2 |
10 |
20 |
11–20 |
|
3 |
20 |
60 |
21–40 |
|
4 |
30 |
120 |
41–70 |
|
5 |
30 |
150 |
71–100 |
|
Total |
100 |
360 |
Step 4 – Cumulative averages.
|
Day |
Buyers |
Sum of ratings |
Cumulative buyers |
Cumulative sum |
Cumulative average |
|
1 |
150 |
450 |
150 |
450 |
3.00 |
|
2 |
50 |
170 |
200 |
620 |
3.10 |
|
3 |
100 |
360 |
300 |
980 |
3.27 |
This question
From Step 2, n = 150. Check: (450 + 170)/(150 + 50) = 620/200 = 3.1 ✓.
Hence, the answer is 150.
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