CAT 2023 Slot 2 · DILR · Set 4: Rides at an Entertainment Park
The full set and all 5 questions (Q16–Q20) from CAT 2023 Slot 2, with answers and solutions.
Anjali, Bipasha, and Chitra visited an entertainment park that has four rides. Each ride lasts one hour and can accommodate one visitor at one point. All rides begin at 9 am and must be completed by 5 pm except for Ride-3, for which the last ride has to be completed by 1 pm. Ride gates open every 30 minutes, e.g. 10 am, 10:30 am, and so on. Whenever a ride gate opens, and there is no visitor inside, the first visitor waiting in the queue buys the ticket just before taking the ride. The ticket prices are Rs. 20, Rs. 50, Rs. 30 and Rs. 40 for Rides 1 to 4, respectively. Each of the three visitors took at least one ride and did not necessarily take all rides. None of them took the same ride more than once. The movement time from one ride to another is negligible, and a visitor leaves the ride immediately after the completion of the ride. No one takes a break inside the park unless mentioned explicitly.
The following information is also known.
1. Chitra never waited in the queue and completed her visit by 11 am after spending Rs. 50 to pay for the ticket(s).
2. Anjali took Ride-1 at 11 am after waiting for 30 mins for Chitra to complete it. It was the only ride where Anjali waited.
3. Bipasha began her first of three rides at 11:30 am. All three visitors incurred the same amount of ticket expense by 12:15 pm.
4. The last ride taken by Anjali and Bipasha was the same, where Bipasha waited 30 mins for Anjali to complete her ride. Before standing in the queue for that ride, Bipasha took a 1-hour coffee break after completing her previous ride.
Question 16 · Caselet DI
- A90
- B120
- C110
- D100
Answer & solution
Answer: Option C
Solving the set
Step 1 – Chitra never waited, finished by 11 am and spent Rs 50: either Ride-2 alone or Ride-1 + Ride-3. Anjali waited from 10:30 to 11:00 for Chitra to finish Ride-1, so Chitra rode Ride-1 from 10 to 11 and must have taken Ride-3 from 9 to 10.
Step 2 – By 12:15 pm everyone spent Rs 50 (fact 3).
• Bipasha's first ride starts at 11:30, so her only ticket by 12:15 cost Rs 50: Ride-2 (11:30–12:30).
• Anjali: Ride-1 at 11:00 (Rs 20). She needs Rs 30 more by 12:15. An earlier Ride-3 is impossible (Chitra was on it 9–10, and Anjali waited only at Ride-1), so she buys Ride-3 at 12:00 (12–1, finishing by the 1 pm limit). No other ride before 11 (it would push her above Rs 50).
Step 3 – Bipasha's second ride starts at 12:30 (no breaks unless stated): Ride-2 is done, Ride-3 cannot finish by 1 pm, and Ride-4 is her last ride, so it is Ride-1 (12:30–1:30). Then a 1-hour coffee break (1:30–2:30), then she queues for her last ride and waits 30 minutes, starting it at 3:00 – Ride-4 (the only ride left).
Step 4 – Anjali was on Ride-4 from 2:00 to 3:00 (Bipasha waited for her). Between 1:00 and 2:00 she cannot take a break, so she rode Ride-2 (free after 12:30).
Time | Ride-1 (Rs 20) | Ride-2 (Rs 50) | Ride-3 (Rs 30) | Ride-4 (Rs 40) |
9:00–10:00 | Chitra | |||
10:00–11:00 | Chitra | |||
11:00–12:00 | Anjali | Bipasha from 11:30 | ||
12:00–1:00 | Bipasha from 12:30 | Bipasha till 12:30 | Anjali | |
1:00–2:00 | Bipasha till 1:30 | Anjali | (closed) | |
2:00–3:00 | Anjali | |||
3:00–4:00 | Bipasha |
Visitor | Rides in order | Spent by 12:15 pm | Total spent |
Chitra | Ride-3 (9–10), Ride-1 (10–11) | 50 | 50 |
Anjali | Ride-1 (11–12), Ride-3 (12–1), Ride-2 (1–2), Ride-4 (2–3) | 20 + 30 = 50 | 140 |
Bipasha | Ride-2 (11:30–12:30), Ride-1 (12:30–1:30), coffee 1:30–2:30, Ride-4 (3–4) | 50 | 110 |
This question
From the table, Bipasha took Ride-2, Ride-1 and Ride-4: 50 + 20 + 40 = Rs 110.
Hence, the answer is option 3.
Question 17 · Caselet DI
- ARide-1 and Ride-3
- BRide-1, Ride-2, and Ride-3
- CRide-1, Ride-2, and Ride-4
- DRide-1 and Ride-4
Answer & solution
Answer: Option B
Solving the set
Step 1 – Chitra never waited, finished by 11 am and spent Rs 50: either Ride-2 alone or Ride-1 + Ride-3. Anjali waited from 10:30 to 11:00 for Chitra to finish Ride-1, so Chitra rode Ride-1 from 10 to 11 and must have taken Ride-3 from 9 to 10.
Step 2 – By 12:15 pm everyone spent Rs 50 (fact 3).
• Bipasha's first ride starts at 11:30, so her only ticket by 12:15 cost Rs 50: Ride-2 (11:30–12:30).
• Anjali: Ride-1 at 11:00 (Rs 20). She needs Rs 30 more by 12:15. An earlier Ride-3 is impossible (Chitra was on it 9–10, and Anjali waited only at Ride-1), so she buys Ride-3 at 12:00 (12–1, finishing by the 1 pm limit). No other ride before 11 (it would push her above Rs 50).
Step 3 – Bipasha's second ride starts at 12:30 (no breaks unless stated): Ride-2 is done, Ride-3 cannot finish by 1 pm, and Ride-4 is her last ride, so it is Ride-1 (12:30–1:30). Then a 1-hour coffee break (1:30–2:30), then she queues for her last ride and waits 30 minutes, starting it at 3:00 – Ride-4 (the only ride left).
Step 4 – Anjali was on Ride-4 from 2:00 to 3:00 (Bipasha waited for her). Between 1:00 and 2:00 she cannot take a break, so she rode Ride-2 (free after 12:30).
Time | Ride-1 (Rs 20) | Ride-2 (Rs 50) | Ride-3 (Rs 30) | Ride-4 (Rs 40) |
9:00–10:00 | Chitra | |||
10:00–11:00 | Chitra | |||
11:00–12:00 | Anjali | Bipasha from 11:30 | ||
12:00–1:00 | Bipasha from 12:30 | Bipasha till 12:30 | Anjali | |
1:00–2:00 | Bipasha till 1:30 | Anjali | (closed) | |
2:00–3:00 | Anjali | |||
3:00–4:00 | Bipasha |
Visitor | Rides in order | Spent by 12:15 pm | Total spent |
Chitra | Ride-3 (9–10), Ride-1 (10–11) | 50 | 50 |
Anjali | Ride-1 (11–12), Ride-3 (12–1), Ride-2 (1–2), Ride-4 (2–3) | 20 + 30 = 50 | 140 |
Bipasha | Ride-2 (11:30–12:30), Ride-1 (12:30–1:30), coffee 1:30–2:30, Ride-4 (3–4) | 50 | 110 |
This question
Anjali's rides: Ride-1 (11–12), Ride-3 (12–1), Ride-2 (1–2), Ride-4 (2–3). By 2:00 pm she had completed Ride-1, Ride-2 and Ride-3.
Hence, the answer is option 2.
Question 18 · Caselet DI
- ARide-1
- BRide-4
- CRide-3
- DRide-2
Answer & solution
Answer: Option A
Solving the set
Step 1 – Chitra never waited, finished by 11 am and spent Rs 50: either Ride-2 alone or Ride-1 + Ride-3. Anjali waited from 10:30 to 11:00 for Chitra to finish Ride-1, so Chitra rode Ride-1 from 10 to 11 and must have taken Ride-3 from 9 to 10.
Step 2 – By 12:15 pm everyone spent Rs 50 (fact 3).
• Bipasha's first ride starts at 11:30, so her only ticket by 12:15 cost Rs 50: Ride-2 (11:30–12:30).
• Anjali: Ride-1 at 11:00 (Rs 20). She needs Rs 30 more by 12:15. An earlier Ride-3 is impossible (Chitra was on it 9–10, and Anjali waited only at Ride-1), so she buys Ride-3 at 12:00 (12–1, finishing by the 1 pm limit). No other ride before 11 (it would push her above Rs 50).
Step 3 – Bipasha's second ride starts at 12:30 (no breaks unless stated): Ride-2 is done, Ride-3 cannot finish by 1 pm, and Ride-4 is her last ride, so it is Ride-1 (12:30–1:30). Then a 1-hour coffee break (1:30–2:30), then she queues for her last ride and waits 30 minutes, starting it at 3:00 – Ride-4 (the only ride left).
Step 4 – Anjali was on Ride-4 from 2:00 to 3:00 (Bipasha waited for her). Between 1:00 and 2:00 she cannot take a break, so she rode Ride-2 (free after 12:30).
Time | Ride-1 (Rs 20) | Ride-2 (Rs 50) | Ride-3 (Rs 30) | Ride-4 (Rs 40) |
9:00–10:00 | Chitra | |||
10:00–11:00 | Chitra | |||
11:00–12:00 | Anjali | Bipasha from 11:30 | ||
12:00–1:00 | Bipasha from 12:30 | Bipasha till 12:30 | Anjali | |
1:00–2:00 | Bipasha till 1:30 | Anjali | (closed) | |
2:00–3:00 | Anjali | |||
3:00–4:00 | Bipasha |
Visitor | Rides in order | Spent by 12:15 pm | Total spent |
Chitra | Ride-3 (9–10), Ride-1 (10–11) | 50 | 50 |
Anjali | Ride-1 (11–12), Ride-3 (12–1), Ride-2 (1–2), Ride-4 (2–3) | 20 + 30 = 50 | 140 |
Bipasha | Ride-2 (11:30–12:30), Ride-1 (12:30–1:30), coffee 1:30–2:30, Ride-4 (3–4) | 50 | 110 |
This question
Ride-1 was taken by Chitra (10–11), Anjali (11–12) and Bipasha (12:30–1:30). No other ride was taken by all three.
Hence, the answer is option 1.
Question 19 · Caselet DI
Answer & solution
Answer: 6
Solving the set
Step 1 – Chitra never waited, finished by 11 am and spent Rs 50: either Ride-2 alone or Ride-1 + Ride-3. Anjali waited from 10:30 to 11:00 for Chitra to finish Ride-1, so Chitra rode Ride-1 from 10 to 11 and must have taken Ride-3 from 9 to 10.
Step 2 – By 12:15 pm everyone spent Rs 50 (fact 3).
• Bipasha's first ride starts at 11:30, so her only ticket by 12:15 cost Rs 50: Ride-2 (11:30–12:30).
• Anjali: Ride-1 at 11:00 (Rs 20). She needs Rs 30 more by 12:15. An earlier Ride-3 is impossible (Chitra was on it 9–10, and Anjali waited only at Ride-1), so she buys Ride-3 at 12:00 (12–1, finishing by the 1 pm limit). No other ride before 11 (it would push her above Rs 50).
Step 3 – Bipasha's second ride starts at 12:30 (no breaks unless stated): Ride-2 is done, Ride-3 cannot finish by 1 pm, and Ride-4 is her last ride, so it is Ride-1 (12:30–1:30). Then a 1-hour coffee break (1:30–2:30), then she queues for her last ride and waits 30 minutes, starting it at 3:00 – Ride-4 (the only ride left).
Step 4 – Anjali was on Ride-4 from 2:00 to 3:00 (Bipasha waited for her). Between 1:00 and 2:00 she cannot take a break, so she rode Ride-2 (free after 12:30).
Time | Ride-1 (Rs 20) | Ride-2 (Rs 50) | Ride-3 (Rs 30) | Ride-4 (Rs 40) |
9:00–10:00 | Chitra | |||
10:00–11:00 | Chitra | |||
11:00–12:00 | Anjali | Bipasha from 11:30 | ||
12:00–1:00 | Bipasha from 12:30 | Bipasha till 12:30 | Anjali | |
1:00–2:00 | Bipasha till 1:30 | Anjali | (closed) | |
2:00–3:00 | Anjali | |||
3:00–4:00 | Bipasha |
Visitor | Rides in order | Spent by 12:15 pm | Total spent |
Chitra | Ride-3 (9–10), Ride-1 (10–11) | 50 | 50 |
Anjali | Ride-1 (11–12), Ride-3 (12–1), Ride-2 (1–2), Ride-4 (2–3) | 20 + 30 = 50 | 140 |
Bipasha | Ride-2 (11:30–12:30), Ride-1 (12:30–1:30), coffee 1:30–2:30, Ride-4 (3–4) | 50 | 110 |
This question
Anjali took 4 rides and Chitra took 2 (Ride-3 and Ride-1). Total = 6.
Hence, the answer is 6.
Question 20 · Caselet DI
Answer & solution
Answer: 140
Solving the set
Step 1 – Chitra never waited, finished by 11 am and spent Rs 50: either Ride-2 alone or Ride-1 + Ride-3. Anjali waited from 10:30 to 11:00 for Chitra to finish Ride-1, so Chitra rode Ride-1 from 10 to 11 and must have taken Ride-3 from 9 to 10.
Step 2 – By 12:15 pm everyone spent Rs 50 (fact 3).
• Bipasha's first ride starts at 11:30, so her only ticket by 12:15 cost Rs 50: Ride-2 (11:30–12:30).
• Anjali: Ride-1 at 11:00 (Rs 20). She needs Rs 30 more by 12:15. An earlier Ride-3 is impossible (Chitra was on it 9–10, and Anjali waited only at Ride-1), so she buys Ride-3 at 12:00 (12–1, finishing by the 1 pm limit). No other ride before 11 (it would push her above Rs 50).
Step 3 – Bipasha's second ride starts at 12:30 (no breaks unless stated): Ride-2 is done, Ride-3 cannot finish by 1 pm, and Ride-4 is her last ride, so it is Ride-1 (12:30–1:30). Then a 1-hour coffee break (1:30–2:30), then she queues for her last ride and waits 30 minutes, starting it at 3:00 – Ride-4 (the only ride left).
Step 4 – Anjali was on Ride-4 from 2:00 to 3:00 (Bipasha waited for her). Between 1:00 and 2:00 she cannot take a break, so she rode Ride-2 (free after 12:30).
Time | Ride-1 (Rs 20) | Ride-2 (Rs 50) | Ride-3 (Rs 30) | Ride-4 (Rs 40) |
9:00–10:00 | Chitra | |||
10:00–11:00 | Chitra | |||
11:00–12:00 | Anjali | Bipasha from 11:30 | ||
12:00–1:00 | Bipasha from 12:30 | Bipasha till 12:30 | Anjali | |
1:00–2:00 | Bipasha till 1:30 | Anjali | (closed) | |
2:00–3:00 | Anjali | |||
3:00–4:00 | Bipasha |
Visitor | Rides in order | Spent by 12:15 pm | Total spent |
Chitra | Ride-3 (9–10), Ride-1 (10–11) | 50 | 50 |
Anjali | Ride-1 (11–12), Ride-3 (12–1), Ride-2 (1–2), Ride-4 (2–3) | 20 + 30 = 50 | 140 |
Bipasha | Ride-2 (11:30–12:30), Ride-1 (12:30–1:30), coffee 1:30–2:30, Ride-4 (3–4) | 50 | 110 |
This question
Anjali: Ride-1 (20) + Ride-3 (30) + Ride-2 (50) + Ride-4 (40) = Rs 140.
Hence, the answer is 140.
Take this paper as a timed test
Real exam timing, instant score, rank and topic-wise analysis.