CAT 2023 Slot 2 · DILR · Set 2: Funds Raised by Five Firms of Odsville
The full set and all 5 questions (Q6–Q10) from CAT 2023 Slot 2, with answers and solutions.
Odsville has five firms - Alfloo, Bzygoo, Czechy, Drjbna and Elavalaki. Each of these firms was founded in some year and also closed down a few years later.
Each firm raised Rs. 1 crore in its first and last year of existence. The amount each firm raised every year increased until it reached a maximum, and then decreased until the firm closed down. No firm raised the same amount of money in two consecutive years. Each annual increase and decrease was either by Rs. 1 crore or by Rs. 2 crores. The table below provides partial information about the five firms.
Firm | First year of existence | Last year of existence | Total amount raised (Rs. crores) |
Alfloo | 2009 | 2016 | 21 |
Bzygoo | 2012 | 2015 | |
Czechy | 2013 | 9 | |
Drjbna | 2011 | 2015 | 10 |
Elavalaki | 2010 | 13 |
Question 6 · Caselet DI
- AOnly Bzygoo and Czechy and Drjbna
- BOnly Czechy and Drjbna
- COnly Drjbna
- DOnly Czechy
Answer & solution
Answer: Option B
Solving the set
Step 1 – Rules for each firm's yearly amounts: start and end at 1, rise (by 1 or 2 each year) to a single peak, then fall (by 1 or 2 each year), never the same in two consecutive years.
Step 2 – List all sequences that fit each firm's years and total:
Firm | Years | Total | Possible yearly amounts (Rs. crores) |
Alfloo | 2009–2016 | 21 | 1, 2, 3, 4, 5, 3, 2, 1 or 1, 2, 3, 5, 4, 3, 2, 1 |
Bzygoo | 2012–2015 | ? | 1, 2, 3, 1 or 1, 3, 2, 1 |
Czechy | 2013–? | 9 | 1, 2, 3, 2, 1 (2013–2017) only |
Drjbna | 2011–2015 | 10 | 1, 2, 4, 2, 1 only |
Elavalaki | 2010–? | 13 | 1, 3, 5, 3, 1 (to 2014) or 1, 2, 3, 4, 2, 1 or 1, 2, 4, 3, 2, 1 (to 2015) |
For example, Drjbna has 5 years totalling 10: 1, a, b, c, 1 with a, b, c adding to 8; only 2, 4, 2 obeys the steps. Czechy totals 9: 1, 2, 3, 2, 1 is the only option (shorter runs total too little, longer ones too much). Bzygoo's total is not given, so both 4-year patterns are possible.
Step 3 – Amounts by year (Elavalaki's three cases separated by /):
Firm | 2012 | 2013 | 2014 | 2015 |
Alfloo | 4 or 5 | 5 or 4 | 3 | 2 |
Bzygoo | 1 | 2 or 3 | 3 or 2 | 1 |
Czechy | — | 1 | 2 | 3 |
Drjbna | 2 | 4 | 2 | 1 |
Elavalaki | 5 / 3 / 4 | 3 / 4 / 3 | 1 / 2 / 2 | — / 1 / 1 |
This question
From Step 2, only Czechy and Drjbna have a unique sequence. Bzygoo has two, Alfloo two and Elavalaki three.
Hence, the answer is option 2.
Question 7 · Caselet DI
- AIt is either Rs. 7 crores or Rs. 8 crores or Rs. 9 crores.
- BIt is exactly Rs. 8 crores.
- CIt is either Rs. 7 crores or Rs. 8 crores.
- DIt is either Rs. 8 crores or Rs. 9 crores.
Answer & solution
Answer: Option C
Solving the set
Step 1 – Rules for each firm's yearly amounts: start and end at 1, rise (by 1 or 2 each year) to a single peak, then fall (by 1 or 2 each year), never the same in two consecutive years.
Step 2 – List all sequences that fit each firm's years and total:
Firm | Years | Total | Possible yearly amounts (Rs. crores) |
Alfloo | 2009–2016 | 21 | 1, 2, 3, 4, 5, 3, 2, 1 or 1, 2, 3, 5, 4, 3, 2, 1 |
Bzygoo | 2012–2015 | ? | 1, 2, 3, 1 or 1, 3, 2, 1 |
Czechy | 2013–? | 9 | 1, 2, 3, 2, 1 (2013–2017) only |
Drjbna | 2011–2015 | 10 | 1, 2, 4, 2, 1 only |
Elavalaki | 2010–? | 13 | 1, 3, 5, 3, 1 (to 2014) or 1, 2, 3, 4, 2, 1 or 1, 2, 4, 3, 2, 1 (to 2015) |
For example, Drjbna has 5 years totalling 10: 1, a, b, c, 1 with a, b, c adding to 8; only 2, 4, 2 obeys the steps. Czechy totals 9: 1, 2, 3, 2, 1 is the only option (shorter runs total too little, longer ones too much). Bzygoo's total is not given, so both 4-year patterns are possible.
Step 3 – Amounts by year (Elavalaki's three cases separated by /):
Firm | 2012 | 2013 | 2014 | 2015 |
Alfloo | 4 or 5 | 5 or 4 | 3 | 2 |
Bzygoo | 1 | 2 or 3 | 3 or 2 | 1 |
Czechy | — | 1 | 2 | 3 |
Drjbna | 2 | 4 | 2 | 1 |
Elavalaki | 5 / 3 / 4 | 3 / 4 / 3 | 1 / 2 / 2 | — / 1 / 1 |
This question
From the 2015 column: Alfloo 2 + Bzygoo 1 + Czechy 3 + Drjbna 1 = 7, plus Elavalaki 0 (if it closed in 2014) or 1. So the total is 7 or 8.
Hence, the answer is option 3.
Question 8 · Caselet DI
Answer & solution
Answer: 17
Solving the set
Step 1 – Rules for each firm's yearly amounts: start and end at 1, rise (by 1 or 2 each year) to a single peak, then fall (by 1 or 2 each year), never the same in two consecutive years.
Step 2 – List all sequences that fit each firm's years and total:
Firm | Years | Total | Possible yearly amounts (Rs. crores) |
Alfloo | 2009–2016 | 21 | 1, 2, 3, 4, 5, 3, 2, 1 or 1, 2, 3, 5, 4, 3, 2, 1 |
Bzygoo | 2012–2015 | ? | 1, 2, 3, 1 or 1, 3, 2, 1 |
Czechy | 2013–? | 9 | 1, 2, 3, 2, 1 (2013–2017) only |
Drjbna | 2011–2015 | 10 | 1, 2, 4, 2, 1 only |
Elavalaki | 2010–? | 13 | 1, 3, 5, 3, 1 (to 2014) or 1, 2, 3, 4, 2, 1 or 1, 2, 4, 3, 2, 1 (to 2015) |
For example, Drjbna has 5 years totalling 10: 1, a, b, c, 1 with a, b, c adding to 8; only 2, 4, 2 obeys the steps. Czechy totals 9: 1, 2, 3, 2, 1 is the only option (shorter runs total too little, longer ones too much). Bzygoo's total is not given, so both 4-year patterns are possible.
Step 3 – Amounts by year (Elavalaki's three cases separated by /):
Firm | 2012 | 2013 | 2014 | 2015 |
Alfloo | 4 or 5 | 5 or 4 | 3 | 2 |
Bzygoo | 1 | 2 or 3 | 3 or 2 | 1 |
Czechy | — | 1 | 2 | 3 |
Drjbna | 2 | 4 | 2 | 1 |
Elavalaki | 5 / 3 / 4 | 3 / 4 / 3 | 1 / 2 / 2 | — / 1 / 1 |
This question
From the 2013 column, take the largest value for each firm: Alfloo 5, Bzygoo 3, Czechy 1, Drjbna 4, Elavalaki 4. Total = 17.
Hence, the answer is 17.
Question 9 · Caselet DI
- A12
- B9
- C11
- D10
Answer & solution
Answer: Option C
Solving the set
Step 1 – Rules for each firm's yearly amounts: start and end at 1, rise (by 1 or 2 each year) to a single peak, then fall (by 1 or 2 each year), never the same in two consecutive years.
Step 2 – List all sequences that fit each firm's years and total:
Firm | Years | Total | Possible yearly amounts (Rs. crores) |
Alfloo | 2009–2016 | 21 | 1, 2, 3, 4, 5, 3, 2, 1 or 1, 2, 3, 5, 4, 3, 2, 1 |
Bzygoo | 2012–2015 | ? | 1, 2, 3, 1 or 1, 3, 2, 1 |
Czechy | 2013–? | 9 | 1, 2, 3, 2, 1 (2013–2017) only |
Drjbna | 2011–2015 | 10 | 1, 2, 4, 2, 1 only |
Elavalaki | 2010–? | 13 | 1, 3, 5, 3, 1 (to 2014) or 1, 2, 3, 4, 2, 1 or 1, 2, 4, 3, 2, 1 (to 2015) |
For example, Drjbna has 5 years totalling 10: 1, a, b, c, 1 with a, b, c adding to 8; only 2, 4, 2 obeys the steps. Czechy totals 9: 1, 2, 3, 2, 1 is the only option (shorter runs total too little, longer ones too much). Bzygoo's total is not given, so both 4-year patterns are possible.
Step 3 – Amounts by year (Elavalaki's three cases separated by /):
Firm | 2012 | 2013 | 2014 | 2015 |
Alfloo | 4 or 5 | 5 or 4 | 3 | 2 |
Bzygoo | 1 | 2 or 3 | 3 or 2 | 1 |
Czechy | — | 1 | 2 | 3 |
Drjbna | 2 | 4 | 2 | 1 |
Elavalaki | 5 / 3 / 4 | 3 / 4 / 3 | 1 / 2 / 2 | — / 1 / 1 |
This question
Elavalaki = 3 in 2013 leaves its first case (2012 = 5) or third case (2012 = 4). For the smallest 2012 total take Alfloo 4, Bzygoo 1, Drjbna 2 and Elavalaki 4 (Czechy starts in 2013): 4 + 1 + 2 + 4 = 11.
Hence, the answer is option 3.
Question 10 · Caselet DI
- ABzygoo raised the same amount of money as Elavalaki in 2013.
- BAlfloo raised the same amount of money as Drjbna in 2013.
- CAlfloo raised the same amount of money as Bzygoo in 2014.
- DBzygoo raised more money than Elavalaki in 2014.
Answer & solution
Answer: Option A
Solving the set
Step 1 – Rules for each firm's yearly amounts: start and end at 1, rise (by 1 or 2 each year) to a single peak, then fall (by 1 or 2 each year), never the same in two consecutive years.
Step 2 – List all sequences that fit each firm's years and total:
Firm | Years | Total | Possible yearly amounts (Rs. crores) |
Alfloo | 2009–2016 | 21 | 1, 2, 3, 4, 5, 3, 2, 1 or 1, 2, 3, 5, 4, 3, 2, 1 |
Bzygoo | 2012–2015 | ? | 1, 2, 3, 1 or 1, 3, 2, 1 |
Czechy | 2013–? | 9 | 1, 2, 3, 2, 1 (2013–2017) only |
Drjbna | 2011–2015 | 10 | 1, 2, 4, 2, 1 only |
Elavalaki | 2010–? | 13 | 1, 3, 5, 3, 1 (to 2014) or 1, 2, 3, 4, 2, 1 or 1, 2, 4, 3, 2, 1 (to 2015) |
For example, Drjbna has 5 years totalling 10: 1, a, b, c, 1 with a, b, c adding to 8; only 2, 4, 2 obeys the steps. Czechy totals 9: 1, 2, 3, 2, 1 is the only option (shorter runs total too little, longer ones too much). Bzygoo's total is not given, so both 4-year patterns are possible.
Step 3 – Amounts by year (Elavalaki's three cases separated by /):
Firm | 2012 | 2013 | 2014 | 2015 |
Alfloo | 4 or 5 | 5 or 4 | 3 | 2 |
Bzygoo | 1 | 2 or 3 | 3 or 2 | 1 |
Czechy | — | 1 | 2 | 3 |
Drjbna | 2 | 4 | 2 | 1 |
Elavalaki | 5 / 3 / 4 | 3 / 4 / 3 | 1 / 2 / 2 | — / 1 / 1 |
This question
2014: Alfloo 3, Czechy 2, Drjbna 2 are fixed, so Bzygoo + Elavalaki = 12 − 7 = 5 ⇒ Bzygoo 3 and Elavalaki 2. Then in 2013 Bzygoo = 2 and Elavalaki = 4 or 3.
• Bzygoo = Elavalaki in 2013: 2 vs 3 or 4 – not possible.
• Alfloo = Drjbna in 2013: Alfloo 4 (second case) = Drjbna 4 – possible.
• Alfloo = Bzygoo in 2014: 3 = 3 – true.
• Bzygoo > Elavalaki in 2014: 3 > 2 – true.
Hence, the answer is option 1.
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