CAT 2023 Slot 2 · DILR · Question 14
CAT 2023 Slot 2 previous year question on Caselet DI, with the answer and a step-by-step solution.
Set 3: Random Draw Competition over Five Days — this question belongs to a set. Read the full set with all 5 questions →
Three participants - Akhil, Bimal and Chatur participate in a random draw competition for five days. Every day, each participant randomly picks up a ball numbered between 1 and 9. The number on the ball determines his score on that day. The total score of a participant is the sum of his scores attained in the five days. The total score of a day is the sum of participants’ scores on that day. The 2-day average on a day, except on Day 1, is the average of the total scores of that day and of the previous day. For example, if the total scores of Day 1 and Day 2 are 25 and 20, then the 2-day average on Day 2 is calculated as 22.5. Table 1 gives the 2-day averages for Days 2 through 5.
Table 1: 2-day averages for Days 2 through 5
Day 2 | Day 3 | Day 4 | Day 5 |
15 | 15.5 | 16 | 17 |
Participants are ranked each day, with the person having the maximum score being awarded the minimum rank (1) on that day. If there is a tie, all participants with the tied score are awarded the best available rank. For example, if on a day Akhil, Bimal, and Chatur score 8, 7 and 7 respectively, then their ranks will be 1, 2 and 2 respectively on that day. These ranks are given in Table 2.
Table 2: Ranks of participants on each day
Day 1 | Day 2 | Day 3 | Day 4 | Day 5 | |
Akhil | 1 | 2 | 2 | 3 | 3 |
Bimal | 2 | 3 | 2 | 1 | 1 |
Chatur | 3 | 1 | 1 | 2 | 2 |
The following information is also known.
1. Chatur always scores in multiples of 3. His score on Day 2 is the unique highest score in the competition. His minimum score is observed only on Day 1, and it matches Akhil’s score on Day 4.
2. The total score on Day 3 is the same as the total score on Day 4.
3. Bimal’s scores are the same on Day 1 and Day 3.
- ACannot be determined
- B5
- C6
- D4
Answer & solution
Answer: Option D
Solving the set
Step 1 – Day totals from the 2-day averages.
Day | 2-day average | Equation | Day total |
1 | — | T1 + T2 = 30 | 15 |
2 | 15 | T2 + T3 = 31 | 15 |
3 | 15.5 | T3 + T4 = 32, T3 = T4 | 16 |
4 | 16 | 16 | |
5 | 17 | T4 + T5 = 34 | 18 |
Step 2 – Chatur scores only 3, 6 or 9. For each day, list the scores that give the day total and the ranks in Table 2.
Day | Total | Ranks (A, B, C) | Possible scores (Akhil, Bimal, Chatur) |
1 | 15 | 1, 2, 3 | (7, 5, 3) or (8, 4, 3) |
2 | 15 | 2, 3, 1 | (4, 2, 9), (5, 1, 9) or (5, 4, 6) |
3 | 16 | 2, 2, 1 | (5, 5, 6) |
4 | 16 | 3, 1, 2 | (1, 9, 6), (2, 8, 6) or (3, 7, 6) |
5 | 18 | 3, 1, 2 | (3, 9, 6), (4, 8, 6) or (5, 7, 6) |
Step 3 – Apply the facts.
• Chatur's Day 2 score is the unique highest in the whole competition, so it is 9: Day 2 is (4, 2, 9) or (5, 1, 9), and no one else ever scores 9 (this removes (1, 9, 6) on Day 4 and (3, 9, 6) on Day 5).
• Chatur's minimum occurs only on Day 1 (3) and equals Akhil's Day 4 score, so Day 4 is (3, 7, 6).
• Bimal scores the same on Days 1 and 3. Day 3 gives Bimal 5, so Day 1 is (7, 5, 3).
• Day 2 (two options) and Day 5 ((4, 8, 6) or (5, 7, 6)) stay open, giving four cases:
Case | Akhil (D1–D5) | Bimal (D1–D5) | Chatur (D1–D5) | Totals A / B / C |
1 | 7, 4, 5, 3, 4 | 5, 2, 5, 7, 8 | 3, 9, 6, 6, 6 | 23 / 27 / 30 |
2 | 7, 4, 5, 3, 5 | 5, 2, 5, 7, 7 | 3, 9, 6, 6, 6 | 24 / 26 / 30 |
3 | 7, 5, 5, 3, 4 | 5, 1, 5, 7, 8 | 3, 9, 6, 6, 6 | 24 / 26 / 30 |
4 | 7, 5, 5, 3, 5 | 5, 1, 5, 7, 7 | 3, 9, 6, 6, 6 | 25 / 25 / 30 |
This question
Only Case 1 gives Bimal a multiple of 3 (27). In Case 1, Akhil's Day 2 score is 4.
Hence, the answer is option 4.
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