CAT 2023 Slot 1 · Quant · Question 21
CAT 2023 Slot 1 previous year question on Permutation and Combination, with the answer and a step-by-step solution.
- A585
- B504
- C648
- D738
Answer & solution
Answer: Option D
Count separately by the number of digits, since the leading-digit rule differs.
Single-digit numbers run from 1 to 9, and a lone digit cannot repeat, so all 9 count.
For two-digit numbers, the tens digit has 9 choices, as it cannot be 0.
The units digit may be any digit other than the one already used, so it has 9 choices.
That gives 9\times 9=81 two-digit numbers.
For three-digit numbers, the hundreds digit has 9 choices, again excluding 0.
The tens digit has 9 remaining choices and the units digit has 8.
That gives 9\times 9\times 8=648 three-digit numbers.
The number 1000 itself repeats the digit 0 three times, so it does not qualify.
The total is 9+81+648=738 — the fourth option.
Shortcut. The pattern of choices is 9, then 9\times 9, then 9\times 9\times 8: the leading digit always loses the zero, and each later digit loses one more already-used digit but regains the zero. Totalling, 9+81+648=738.
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