CAT 2022 Slot 2 · DILR · Set 1: TRICCEK Salesmen

The full set and all 5 questions (Q1–Q5) from CAT 2022 Slot 2, with answers and solutions.

A few salesmen are employed to sell a product called TRICCEK among households in various housing complexes. On each day, a salesman is assigned to visit one housing complex. Once a salesman enters a housing complex, he can meet any number of households in the time available. However, if a household makes a complaint against the salesman, then he must leave the housing complex immediately and cannot meet any other household on that day. A household may buy any number of TRICCEK items or may not buy any item. The salesman needs to record the total number of TRICCEK items sold as well as the number of households met in each day. The success rate of a salesman for a day is defined as the ratio of the number of items sold to the number of households met on that day. Some details about the performances of three salesmen - Tohri, Hokli and Lahur, on two particular days are given below.

1. Over the two days, all three of them met the same total number of households, and each of them sold a total of 100 items.

2. On both days, Lahur met the same number of households and sold the same number of items.

3. Hokli could not sell any item on the second day because the first household he met on that day complained against him.

4. Tohri met 30 more households on the second day than on the first day.

5. Tohri’s success rate was twice that of Lahur’s on the first day, and it was 75% of Lahur’s on the second day.

Question 1 · Caselet DI

What was the total number of households met by Tohri, Hokli and Lahur on the first day?
Answer & solution

Answer: 84

Solving the set

Step 1 – Lahur meets h households and sells s items each day (fact 2), so 2s = 100 ⇒ s = 50 per day. All three met the same total, N = 2h.

Step 2 – Hokli met just 1 household on Day 2 (sold 0), so on Day 1 he met N − 1 households and sold 100 items.

Step 3 – Tohri meets t on Day 1 and t + 30 on Day 2: 2t + 30 = 2h ⇒ h = t + 15. Let Tohri sell x items on Day 1 and 100 − x on Day 2.

Step 4 – Fact 5. Day 1: x/t = 2 × 50/(t + 15) ⇒ x = 100t/(t + 15). Day 2: (100 − x)/(t + 30) = 0.75 × 50/(t + 15). Since 100 − x = 1500/(t + 15), this gives 1500 = 37.5(t + 30) ⇒ t = 10, x = 40, h = 25, N = 50.

Salesman

Day 1 households

Day 1 items

Day 1 success rate

Day 2 households

Day 2 items

Day 2 success rate

Total households

Total items

Tohri

10

40

4.00

40

60

1.50

50

100

Hokli

49

100

2.04

1

0

0

50

100

Lahur

25

50

2.00

25

50

2.00

50

100

Total

84

190

66

110

150

300

This question

From the table, Day 1 households: Tohri 10 + Hokli 49 + Lahur 25 = 84.

Hence, the answer is 84.

Question 2 · Caselet DI

How many TRICCEK items were sold by Tohri on the first day?
Answer & solution

Answer: 40

Solving the set

Step 1 – Lahur meets h households and sells s items each day (fact 2), so 2s = 100 ⇒ s = 50 per day. All three met the same total, N = 2h.

Step 2 – Hokli met just 1 household on Day 2 (sold 0), so on Day 1 he met N − 1 households and sold 100 items.

Step 3 – Tohri meets t on Day 1 and t + 30 on Day 2: 2t + 30 = 2h ⇒ h = t + 15. Let Tohri sell x items on Day 1 and 100 − x on Day 2.

Step 4 – Fact 5. Day 1: x/t = 2 × 50/(t + 15) ⇒ x = 100t/(t + 15). Day 2: (100 − x)/(t + 30) = 0.75 × 50/(t + 15). Since 100 − x = 1500/(t + 15), this gives 1500 = 37.5(t + 30) ⇒ t = 10, x = 40, h = 25, N = 50.

Salesman

Day 1 households

Day 1 items

Day 1 success rate

Day 2 households

Day 2 items

Day 2 success rate

Total households

Total items

Tohri

10

40

4.00

40

60

1.50

50

100

Hokli

49

100

2.04

1

0

0

50

100

Lahur

25

50

2.00

25

50

2.00

50

100

Total

84

190

66

110

150

300

This question

From Step 4, Tohri sold x = 40 items on Day 1.

Hence, the answer is 40.

Question 3 · Caselet DI

How many households did Lahur meet on the second day?
  1. A
    between 21 and 29
  2. B
    20 or less
  3. C
    more than 35
  4. D
    between 30 and 35
Pick an option, then check.
Answer & solution

Answer: Option A

Solving the set

Step 1 – Lahur meets h households and sells s items each day (fact 2), so 2s = 100 ⇒ s = 50 per day. All three met the same total, N = 2h.

Step 2 – Hokli met just 1 household on Day 2 (sold 0), so on Day 1 he met N − 1 households and sold 100 items.

Step 3 – Tohri meets t on Day 1 and t + 30 on Day 2: 2t + 30 = 2h ⇒ h = t + 15. Let Tohri sell x items on Day 1 and 100 − x on Day 2.

Step 4 – Fact 5. Day 1: x/t = 2 × 50/(t + 15) ⇒ x = 100t/(t + 15). Day 2: (100 − x)/(t + 30) = 0.75 × 50/(t + 15). Since 100 − x = 1500/(t + 15), this gives 1500 = 37.5(t + 30) ⇒ t = 10, x = 40, h = 25, N = 50.

Salesman

Day 1 households

Day 1 items

Day 1 success rate

Day 2 households

Day 2 items

Day 2 success rate

Total households

Total items

Tohri

10

40

4.00

40

60

1.50

50

100

Hokli

49

100

2.04

1

0

0

50

100

Lahur

25

50

2.00

25

50

2.00

50

100

Total

84

190

66

110

150

300

This question

From Step 4, Lahur met h = 25 households each day, which is between 21 and 29.

Hence, the answer is option 1.

Question 4 · Caselet DI

How many households did Tohri meet on the first day?
  1. A
    between 21 and 40
  2. B
    between 11 and 20
  3. C
    more than 40
  4. D
    10 or less
Pick an option, then check.
Answer & solution

Answer: Option D

Solving the set

Step 1 – Lahur meets h households and sells s items each day (fact 2), so 2s = 100 ⇒ s = 50 per day. All three met the same total, N = 2h.

Step 2 – Hokli met just 1 household on Day 2 (sold 0), so on Day 1 he met N − 1 households and sold 100 items.

Step 3 – Tohri meets t on Day 1 and t + 30 on Day 2: 2t + 30 = 2h ⇒ h = t + 15. Let Tohri sell x items on Day 1 and 100 − x on Day 2.

Step 4 – Fact 5. Day 1: x/t = 2 × 50/(t + 15) ⇒ x = 100t/(t + 15). Day 2: (100 − x)/(t + 30) = 0.75 × 50/(t + 15). Since 100 − x = 1500/(t + 15), this gives 1500 = 37.5(t + 30) ⇒ t = 10, x = 40, h = 25, N = 50.

Salesman

Day 1 households

Day 1 items

Day 1 success rate

Day 2 households

Day 2 items

Day 2 success rate

Total households

Total items

Tohri

10

40

4.00

40

60

1.50

50

100

Hokli

49

100

2.04

1

0

0

50

100

Lahur

25

50

2.00

25

50

2.00

50

100

Total

84

190

66

110

150

300

This question

From Step 4, Tohri met 10 households on Day 1 (10 or less).

Hence, the answer is option 4.

Question 5 · Caselet DI

Which of the following statements is FALSE?
  1. A
    Among the three, Tohri had the highest success rate on the second day.
  2. B
    Tohri had a higher success rate on the first day compared to the second day.
  3. C
    Among the three, Tohri had the highest success rate on the first day.
  4. D
    Among the three, Lahur had the lowest success rate on the first day.
Pick an option, then check.
Answer & solution

Answer: Option A

Solving the set

Step 1 – Lahur meets h households and sells s items each day (fact 2), so 2s = 100 ⇒ s = 50 per day. All three met the same total, N = 2h.

Step 2 – Hokli met just 1 household on Day 2 (sold 0), so on Day 1 he met N − 1 households and sold 100 items.

Step 3 – Tohri meets t on Day 1 and t + 30 on Day 2: 2t + 30 = 2h ⇒ h = t + 15. Let Tohri sell x items on Day 1 and 100 − x on Day 2.

Step 4 – Fact 5. Day 1: x/t = 2 × 50/(t + 15) ⇒ x = 100t/(t + 15). Day 2: (100 − x)/(t + 30) = 0.75 × 50/(t + 15). Since 100 − x = 1500/(t + 15), this gives 1500 = 37.5(t + 30) ⇒ t = 10, x = 40, h = 25, N = 50.

Salesman

Day 1 households

Day 1 items

Day 1 success rate

Day 2 households

Day 2 items

Day 2 success rate

Total households

Total items

Tohri

10

40

4.00

40

60

1.50

50

100

Hokli

49

100

2.04

1

0

0

50

100

Lahur

25

50

2.00

25

50

2.00

50

100

Total

84

190

66

110

150

300

This question

Success rates from the table – Day 1: Tohri 4, Hokli 2.04, Lahur 2; Day 2: Tohri 1.5, Hokli 0, Lahur 2.

• 'Tohri highest on Day 2' – false (Lahur's 2 is higher).

• 'Tohri higher on Day 1 than Day 2' – true (4 > 1.5).

• 'Tohri highest on Day 1' – true. 'Lahur lowest on Day 1' – true (2 < 2.04 < 4).

Hence, the answer is option 1.

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