CAT 2022 Slot 1 · DILR · Set 3: Funding Tokens from Six Interviewers
The full set and all 5 questions (Q11–Q15) from CAT 2022 Slot 1, with answers and solutions.
Adhara, Bithi, Chhaya, Dhanavi, Esther, and Fathima are the interviewers in a process that awards funding for new initiatives. Every interviewer individually interviews each of the candidates individually and awards a token only if she recommends funding. A token has a face value of 2, 3, 5, 7, 11, or 13. Each interviewer awards tokens of a single face value only.
Once all six interviews are over for a candidate, the candidate receives a funding that is Rs.1000 times the product of the face values of all the tokens. For example, if a candidate has tokens with face values 2, 5, and 7, then they get a funding of Rs.1000 × (2 × 5 × 7) = Rs.70,000.
Pragnyaa, Qahira, Rasheeda, Smera, and Tantra were five candidates who received funding. The funds they received, in descending order, were Rs.390,000, Rs.210,000, Rs.165,000, Rs.77,000, and Rs.66,000.
The following additional facts are known:
1. Fathima awarded tokens to everyone except Qahira, while Adhara awarded tokens to no one except Pragnyaa.
2. Rashida received the highest number of tokens that anyone received, but she did not receive one from Esther.
3. Bithi awarded a token to Smera but not to Qahira, while Dhanavi awarded a token to Qahira but not to Smera.
Question 11 · Caselet DI
Answer & solution
Answer: 2
Solving the set
Step 1 – Factorise each funding amount (÷ 1000). Every amount is a product of distinct primes, so each interviewer has a different face value.
Funding (Rs.) | ÷ 1000 | Prime factors (tokens) | Number of tokens |
390,000 | 390 | 2 × 3 × 5 × 13 | 4 |
210,000 | 210 | 2 × 3 × 5 × 7 | 4 |
165,000 | 165 | 3 × 5 × 11 | 3 |
77,000 | 77 | 7 × 11 | 2 |
66,000 | 66 | 2 × 3 × 11 | 3 |
Step 2 – Count how often each value appears: 2 → 3 amounts, 3 → 4, 5 → 3, 7 → 2, 11 → 3, 13 → 1.
Step 3 – Fathima gives to four candidates (all but Qahira) ⇒ her value is 3, and Qahira has 77,000. Adhara gives only to Pragnyaa ⇒ value 13, and Pragnyaa has 390,000.
Step 4 – Rasheeda has the most tokens (4) and is not Pragnyaa ⇒ 210,000 (2, 3, 5, 7). She got nothing from Esther, so Esther's value is not 2, 3, 5 or 7, and not 13 (Adhara) ⇒ 11.
Step 5 – Dhanavi gives Qahira (7 × 11); 11 is Esther's ⇒ Dhanavi = 7. Bithi and Chhaya take 2 and 5. Smera and Tantra get 165,000 and 66,000; Bithi gives Smera, so Bithi = 5 ⇒ Smera 165,000, or Bithi = 2 ⇒ Smera 66,000. Both are consistent.
Interviewer | Face value | Reason |
Fathima | 3 | Only 3 appears in exactly four amounts (all except 77,000 = Qahira) |
Adhara | 13 | Only 13 appears in exactly one amount (390,000 = Pragnyaa) |
Esther | 11 | Rasheeda (4 tokens, 210,000 = 2·3·5·7) has no Esther token; 11 is the only value she lacks among 2, 5, 7, 11 |
Dhanavi | 7 | Gives Qahira (7 × 11); 11 is Esther's |
Bithi | 2 or 5 | Gives Smera |
Chhaya | 5 or 2 | The remaining value |
Candidate | Funding (Rs.) | Tokens from |
Pragnyaa | 390,000 | Adhara (13), Fathima (3), Bithi and Chhaya (2, 5) |
Rasheeda | 210,000 | Fathima (3), Dhanavi (7), Bithi and Chhaya (2, 5) |
Qahira | 77,000 | Dhanavi (7), Esther (11) |
Smera / Tantra | 165,000 and 66,000 in some order | Fathima (3), Esther (11) and one of Bithi/Chhaya |
This question
From Step 3, Qahira's funding is 77,000 = 7 × 11: tokens from Dhanavi and Esther. 2 tokens.
Hence, the answer is 2.
Question 12 · Caselet DI
- APragnyaa
- BRasheeda
- CQahira
- DTantra
Answer & solution
Answer: Option A
Solving the set
Step 1 – Factorise each funding amount (÷ 1000). Every amount is a product of distinct primes, so each interviewer has a different face value.
Funding (Rs.) | ÷ 1000 | Prime factors (tokens) | Number of tokens |
390,000 | 390 | 2 × 3 × 5 × 13 | 4 |
210,000 | 210 | 2 × 3 × 5 × 7 | 4 |
165,000 | 165 | 3 × 5 × 11 | 3 |
77,000 | 77 | 7 × 11 | 2 |
66,000 | 66 | 2 × 3 × 11 | 3 |
Step 2 – Count how often each value appears: 2 → 3 amounts, 3 → 4, 5 → 3, 7 → 2, 11 → 3, 13 → 1.
Step 3 – Fathima gives to four candidates (all but Qahira) ⇒ her value is 3, and Qahira has 77,000. Adhara gives only to Pragnyaa ⇒ value 13, and Pragnyaa has 390,000.
Step 4 – Rasheeda has the most tokens (4) and is not Pragnyaa ⇒ 210,000 (2, 3, 5, 7). She got nothing from Esther, so Esther's value is not 2, 3, 5 or 7, and not 13 (Adhara) ⇒ 11.
Step 5 – Dhanavi gives Qahira (7 × 11); 11 is Esther's ⇒ Dhanavi = 7. Bithi and Chhaya take 2 and 5. Smera and Tantra get 165,000 and 66,000; Bithi gives Smera, so Bithi = 5 ⇒ Smera 165,000, or Bithi = 2 ⇒ Smera 66,000. Both are consistent.
Interviewer | Face value | Reason |
Fathima | 3 | Only 3 appears in exactly four amounts (all except 77,000 = Qahira) |
Adhara | 13 | Only 13 appears in exactly one amount (390,000 = Pragnyaa) |
Esther | 11 | Rasheeda (4 tokens, 210,000 = 2·3·5·7) has no Esther token; 11 is the only value she lacks among 2, 5, 7, 11 |
Dhanavi | 7 | Gives Qahira (7 × 11); 11 is Esther's |
Bithi | 2 or 5 | Gives Smera |
Chhaya | 5 or 2 | The remaining value |
Candidate | Funding (Rs.) | Tokens from |
Pragnyaa | 390,000 | Adhara (13), Fathima (3), Bithi and Chhaya (2, 5) |
Rasheeda | 210,000 | Fathima (3), Dhanavi (7), Bithi and Chhaya (2, 5) |
Qahira | 77,000 | Dhanavi (7), Esther (11) |
Smera / Tantra | 165,000 and 66,000 in some order | Fathima (3), Esther (11) and one of Bithi/Chhaya |
This question
Bithi's value is 2 or 5; Dhanavi's is 7.
• Pragnyaa (2 × 3 × 5 × 13) has both 2 and 5, so she gets Bithi's token in either case, and she has no 7 – she definitely fits.
• Rasheeda has 7, so she has Dhanavi's token. Qahira has no token from Bithi. Tantra gets Bithi's token only in one of the two cases.
Hence, the answer is option 1.
Question 13 · Caselet DI
Answer & solution
Answer: 3
Solving the set
Step 1 – Factorise each funding amount (÷ 1000). Every amount is a product of distinct primes, so each interviewer has a different face value.
Funding (Rs.) | ÷ 1000 | Prime factors (tokens) | Number of tokens |
390,000 | 390 | 2 × 3 × 5 × 13 | 4 |
210,000 | 210 | 2 × 3 × 5 × 7 | 4 |
165,000 | 165 | 3 × 5 × 11 | 3 |
77,000 | 77 | 7 × 11 | 2 |
66,000 | 66 | 2 × 3 × 11 | 3 |
Step 2 – Count how often each value appears: 2 → 3 amounts, 3 → 4, 5 → 3, 7 → 2, 11 → 3, 13 → 1.
Step 3 – Fathima gives to four candidates (all but Qahira) ⇒ her value is 3, and Qahira has 77,000. Adhara gives only to Pragnyaa ⇒ value 13, and Pragnyaa has 390,000.
Step 4 – Rasheeda has the most tokens (4) and is not Pragnyaa ⇒ 210,000 (2, 3, 5, 7). She got nothing from Esther, so Esther's value is not 2, 3, 5 or 7, and not 13 (Adhara) ⇒ 11.
Step 5 – Dhanavi gives Qahira (7 × 11); 11 is Esther's ⇒ Dhanavi = 7. Bithi and Chhaya take 2 and 5. Smera and Tantra get 165,000 and 66,000; Bithi gives Smera, so Bithi = 5 ⇒ Smera 165,000, or Bithi = 2 ⇒ Smera 66,000. Both are consistent.
Interviewer | Face value | Reason |
Fathima | 3 | Only 3 appears in exactly four amounts (all except 77,000 = Qahira) |
Adhara | 13 | Only 13 appears in exactly one amount (390,000 = Pragnyaa) |
Esther | 11 | Rasheeda (4 tokens, 210,000 = 2·3·5·7) has no Esther token; 11 is the only value she lacks among 2, 5, 7, 11 |
Dhanavi | 7 | Gives Qahira (7 × 11); 11 is Esther's |
Bithi | 2 or 5 | Gives Smera |
Chhaya | 5 or 2 | The remaining value |
Candidate | Funding (Rs.) | Tokens from |
Pragnyaa | 390,000 | Adhara (13), Fathima (3), Bithi and Chhaya (2, 5) |
Rasheeda | 210,000 | Fathima (3), Dhanavi (7), Bithi and Chhaya (2, 5) |
Qahira | 77,000 | Dhanavi (7), Esther (11) |
Smera / Tantra | 165,000 and 66,000 in some order | Fathima (3), Esther (11) and one of Bithi/Chhaya |
This question
If Chhaya's value is 2, she gives to Pragnyaa, Rasheeda and the 66,000 candidate; if it is 5, to Pragnyaa, Rasheeda and the 165,000 candidate. Either way 3 tokens.
Hence, the answer is 3.
Question 14 · Caselet DI
Answer & solution
Answer: 3
Solving the set
Step 1 – Factorise each funding amount (÷ 1000). Every amount is a product of distinct primes, so each interviewer has a different face value.
Funding (Rs.) | ÷ 1000 | Prime factors (tokens) | Number of tokens |
390,000 | 390 | 2 × 3 × 5 × 13 | 4 |
210,000 | 210 | 2 × 3 × 5 × 7 | 4 |
165,000 | 165 | 3 × 5 × 11 | 3 |
77,000 | 77 | 7 × 11 | 2 |
66,000 | 66 | 2 × 3 × 11 | 3 |
Step 2 – Count how often each value appears: 2 → 3 amounts, 3 → 4, 5 → 3, 7 → 2, 11 → 3, 13 → 1.
Step 3 – Fathima gives to four candidates (all but Qahira) ⇒ her value is 3, and Qahira has 77,000. Adhara gives only to Pragnyaa ⇒ value 13, and Pragnyaa has 390,000.
Step 4 – Rasheeda has the most tokens (4) and is not Pragnyaa ⇒ 210,000 (2, 3, 5, 7). She got nothing from Esther, so Esther's value is not 2, 3, 5 or 7, and not 13 (Adhara) ⇒ 11.
Step 5 – Dhanavi gives Qahira (7 × 11); 11 is Esther's ⇒ Dhanavi = 7. Bithi and Chhaya take 2 and 5. Smera and Tantra get 165,000 and 66,000; Bithi gives Smera, so Bithi = 5 ⇒ Smera 165,000, or Bithi = 2 ⇒ Smera 66,000. Both are consistent.
Interviewer | Face value | Reason |
Fathima | 3 | Only 3 appears in exactly four amounts (all except 77,000 = Qahira) |
Adhara | 13 | Only 13 appears in exactly one amount (390,000 = Pragnyaa) |
Esther | 11 | Rasheeda (4 tokens, 210,000 = 2·3·5·7) has no Esther token; 11 is the only value she lacks among 2, 5, 7, 11 |
Dhanavi | 7 | Gives Qahira (7 × 11); 11 is Esther's |
Bithi | 2 or 5 | Gives Smera |
Chhaya | 5 or 2 | The remaining value |
Candidate | Funding (Rs.) | Tokens from |
Pragnyaa | 390,000 | Adhara (13), Fathima (3), Bithi and Chhaya (2, 5) |
Rasheeda | 210,000 | Fathima (3), Dhanavi (7), Bithi and Chhaya (2, 5) |
Qahira | 77,000 | Dhanavi (7), Esther (11) |
Smera / Tantra | 165,000 and 66,000 in some order | Fathima (3), Esther (11) and one of Bithi/Chhaya |
This question
Smera's funding is 165,000 or 66,000; each is a product of three primes, so she got 3 tokens.
Hence, the answer is 3.
Question 15 · Caselet DI
Which of the following could be the amount of funding that Tantra received?
(a) Rs. 66,000
(b) Rs. 165,000
- ANeither (a) nor (b)
- BOnly (b)
- COnly (a)
- DBoth (a) and (b)
Answer & solution
Answer: Option D
Solving the set
Step 1 – Factorise each funding amount (÷ 1000). Every amount is a product of distinct primes, so each interviewer has a different face value.
Funding (Rs.) | ÷ 1000 | Prime factors (tokens) | Number of tokens |
390,000 | 390 | 2 × 3 × 5 × 13 | 4 |
210,000 | 210 | 2 × 3 × 5 × 7 | 4 |
165,000 | 165 | 3 × 5 × 11 | 3 |
77,000 | 77 | 7 × 11 | 2 |
66,000 | 66 | 2 × 3 × 11 | 3 |
Step 2 – Count how often each value appears: 2 → 3 amounts, 3 → 4, 5 → 3, 7 → 2, 11 → 3, 13 → 1.
Step 3 – Fathima gives to four candidates (all but Qahira) ⇒ her value is 3, and Qahira has 77,000. Adhara gives only to Pragnyaa ⇒ value 13, and Pragnyaa has 390,000.
Step 4 – Rasheeda has the most tokens (4) and is not Pragnyaa ⇒ 210,000 (2, 3, 5, 7). She got nothing from Esther, so Esther's value is not 2, 3, 5 or 7, and not 13 (Adhara) ⇒ 11.
Step 5 – Dhanavi gives Qahira (7 × 11); 11 is Esther's ⇒ Dhanavi = 7. Bithi and Chhaya take 2 and 5. Smera and Tantra get 165,000 and 66,000; Bithi gives Smera, so Bithi = 5 ⇒ Smera 165,000, or Bithi = 2 ⇒ Smera 66,000. Both are consistent.
Interviewer | Face value | Reason |
Fathima | 3 | Only 3 appears in exactly four amounts (all except 77,000 = Qahira) |
Adhara | 13 | Only 13 appears in exactly one amount (390,000 = Pragnyaa) |
Esther | 11 | Rasheeda (4 tokens, 210,000 = 2·3·5·7) has no Esther token; 11 is the only value she lacks among 2, 5, 7, 11 |
Dhanavi | 7 | Gives Qahira (7 × 11); 11 is Esther's |
Bithi | 2 or 5 | Gives Smera |
Chhaya | 5 or 2 | The remaining value |
Candidate | Funding (Rs.) | Tokens from |
Pragnyaa | 390,000 | Adhara (13), Fathima (3), Bithi and Chhaya (2, 5) |
Rasheeda | 210,000 | Fathima (3), Dhanavi (7), Bithi and Chhaya (2, 5) |
Qahira | 77,000 | Dhanavi (7), Esther (11) |
Smera / Tantra | 165,000 and 66,000 in some order | Fathima (3), Esther (11) and one of Bithi/Chhaya |
This question
From Step 5, Tantra's funding is 66,000 when Bithi's value is 5, and 165,000 when it is 2. Both cases are valid.
Hence, the answer is option 4.
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