CAT 2021 Slot 3 · Quant · Question 19
CAT 2021 Slot 3 previous year question on Maxima and Minima, with the answer and a step-by-step solution.
- A90000
- B160000
- C120000
- D100000
Answer & solution
Answer: Option C
Let the expensive side have length L and the other dimension be W, so LW=60000.
The side opposite the expensive one also has length L but costs 100 per ft, and the two sides of length W cost 100 per ft each. So the total cost is
C=200L+100L+2\left( 100W \right)=300L+200W.
Substituting W=\frac{60000}{L} gives C=300L+\frac{12000000}{L}.
Both terms are positive, so by AM-GM their sum is least when they are equal, and C\ge 2\sqrt{300L\cdot \frac{12000000}{L}}=2\sqrt{3600000000}=2\times 60000=120000.
The minimum ₹120000 is reached when 300L=\frac{12000000}{L}, that is L=200 ft and W=300 ft.
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