CAT 2021 Slot 3 · DILR · Question 14

CAT 2021 Slot 3 previous year question on Caselet DI, with the answer and a step-by-step solution.

Caselet DIData InterpretationMultiple choiceHard

Set 3: Javelin Throw Event — this question belongs to a set. Read the full set with all 6 questions →

10 players - P1, P2, … , P10 - competed in an international javelin throw event. The number (after P) of a player reflects his rank at the beginning of the event, with rank 1 going to the topmost player. There were two phases in the event with the first phase consisting of rounds 1, 2, and 3, and the second phase consisting of rounds 4, 5, and 6. A throw is measured in terms of the distance it covers (in meters, up to one decimal point accuracy), only if the throw is a ‘valid’ one. For an invalid throw, the distance is taken as zero. A player’s score at the end of a round is the maximum distance of all his throws up to that round. Players are re-ranked after every round based on their current scores. In case of a tie in scores, the player with a prevailing higher rank retains the higher rank. This ranking determines the order in which the players go for their throws in the next round.

In each of the rounds in the first phase, the players throw in increasing order of their latest rank, i.e. the player ranked 1 at that point throws first, followed by the player ranked 2 at that point and so on. The top six players at the end of the first phase qualify for the second phase. In each of the rounds in the second phase, the players throw in decreasing order of their latest rank i.e. the player ranked 6 at that point throws first, followed by the player ranked 5 at that point and so on. The players ranked 1, 2, and 3 at the end of the sixth round receive gold, silver, and bronze medals respectively.

All the valid throws of the event were of distinct distances (as per stated measurement accuracy). The tables below show distances (in meters) covered by all valid throws in the first and the third round in the event.

Distances covered by all the valid throws in the first round

Player

Distance (in m)

P1

82.9

P3

81.5

P5

86.4

P6

82.5

P7

87.2

P9

84.1

Distances covered by all the valid throws in the third round

Player

Distance (in m)

P1

88.6

P3

79.0

P9

81.4

The following facts are also known.

i. Among the throws in the second round, only the last two were valid. Both the throws enabled these players to qualify for the second phase, with one of them qualifying with the least score. None of these players won any medal.

ii. If a player throws first in a round AND he was also the last (among the players in the current round) to throw in the previous round, then the player is said to get a double. Two players got a double.

iii. In each round of the second phase, exactly one player improved his score. Each of these improvements was by the same amount.

iv. The gold and bronze medalists improved their scores in the fifth and the sixth rounds respectively. One medal winner improved his score in the fourth round.

v. The difference between the final scores of the gold medalist and the silver medalist, as well as the difference between the final scores of the silver medalist and the bronze medalist was 1.0 m.

By how much did the gold medalist improve his score (in m) in the second phase?
  1. A
    1.0
  2. B
    2.0
  3. C
    2.4
  4. D
    1.2
Pick an option, then check.
Answer & solution

Answer: Option C

Solving the set

Step 1 – After Round 1 the ranking is P7 87.2, P5 86.4, P9 84.1, P1 82.9, P6 82.5, P3 81.5, then P2, P4, P8, P10 (no valid throw, original order kept).

Step 2 – Round 2 is thrown in that order, so the last two throwers are P8 and P10, and only their throws are valid (fact i). After Round 3 (P1 88.6; P3 and P9 do not improve), both P8 and P10 must be in the top six, so both beat P6's 82.5, and one of them is 6th (below P9's 84.1).

Step 3 – Medals (facts iii–v). The medalists come from P1, P7, P5, P9 (P8 and P10 win nothing). Gold improves in Round 5, bronze in Round 6, and some medalist in Round 4, all by the same amount d, with gold − silver = silver − bronze = 1.0. The only consistent case: d = 1.2, P7 improves in Rounds 4 and 5 (87.2 → 89.6, gold), P1 stays at 88.6 (silver), P5 improves in Round 6 (86.4 → 87.6, bronze).

Step 4 – Doubles (fact ii). Possible only in Round 3 (if P10, last in Round 2, leads after Round 2) and in Round 4 (if the qualifier who threw last in Round 3 is ranked 6th after Round 3). Two doubles are needed. So P10 scored above 87.2 in Round 2 (but below the bronze score 87.6) and threw first in Round 3. For the Round 4 double, the qualifier who threw last in Round 3 must be ranked 6th after Round 3: that is P8, and he must have been below P1's 82.9 after Round 2 (otherwise P1 would have thrown after him). So P8's score is between 82.5 and 82.9.

Rank after Round 3

Player

Score (m)

Source of score

1

P1

88.6

Round 3

2

P10

87.3 to 87.5

Round 2 (last valid throw of Round 2)

3

P7

87.2

Round 1

4

P5

86.4

Round 1

5

P9

84.1

Round 1

6

P8

between 82.5 and 82.9

Round 2

7–10

P6, P3, P2, P4

82.5, 81.5, 0, 0

Did not qualify

Round

Throwing order (rank 6 first)

Improver

Ranking after the round

4

P8, P9, P5, P7, P10, P1

P7 (+1.2 → 88.4)

P1, P7, P10, P5, P9, P8

5

P8, P9, P5, P10, P7, P1

P7 (+1.2 → 89.6)

P7, P1, P10, P5, P9, P8

6

P8, P9, P5, P10, P1, P7

P5 (+1.2 → 87.6)

P7, P1, P5, P10, P9, P8

Medal

Player

Final score (m)

Gold

P7

89.6 (improved 2.4 in Rounds 4 and 5)

Silver

P1

88.6

Bronze

P5

87.6 (improved in Round 6)

This question

P7 went from 87.2 to 89.6 in Phase 2: an improvement of 2 × 1.2 = 2.4 m.

Hence, the answer is option 3.

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